5 l o g 2 l o g 5 {\displaystyle 5^{\frac {log2}{log5}}}
5 l o g 2 l o g 5 5 l o g 10 2 l o g 10 5 log a ( b ) = log c ( b ) log c ( a ) l o g 10 2 = l o g 5 2 l o g 5 10 log 10 5 = l o g 5 5 l o g 5 10 5 l o g 5 2 l o g 5 10 ∗ l o g 5 10 l o g 5 5 5 l o g 5 2 l o g 5 10 ∗ l o g 5 10 1 5 l o g 5 2 = 2 {\displaystyle {\begin{aligned}5^{\frac {log2}{log5}}\\5^{\frac {log_{10}2}{log_{10}5}}\\{\displaystyle \log _{a}(b)={\frac {\log _{c}(b)}{\log _{c}(a)}}}\\log_{10}2={\frac {log_{5}2}{log_{5}10}}\ \ \ \ \ \ \ \ \log _{10}5={\frac {log_{5}5}{log_{5}10}}\\5^{{\frac {log_{5}2}{log_{5}10}}*{\frac {log_{5}10}{log_{5}5}}}\\5^{{\frac {log_{5}2}{log_{5}10}}*{\frac {log_{5}10}{1}}}\\5^{log_{5}2}=2\\\end{aligned}}}