5 − x | x + 1 | > 2 5 − x > 2 | x + 1 | − ( 5 − x ) < 2 ( x + 1 ) < 5 − x {\displaystyle {\begin{aligned}&{\frac {5-x}{|x+1|}}>2\\&5-x>2|x+1|\\&-(5-x)<2(x+1)<5-x\\\end{aligned}}}
2 x + 2 < 5 − x 3 x < 3 x < 1 {\displaystyle {\begin{aligned}&2x+2<5-x\\&3x<3\\&x<1\\\end{aligned}}}
− 7 < x < 1 {\displaystyle {\begin{aligned}-7<x<1\end{aligned}}}
