log1108+log1105−log1102
log1108+log1105−log1102log110(8+5−2)log110(232+512−2)log110(222∗212+512−2)log110(212+512)ab=x⇔loga(x)=b110=(2∗5)12(10)−x=(2∗5)12(2∗5)−x=(2∗5)12x=−12